Hello! We can solve this exercise using proportionality.
Let's look at the triangles:
In the smallest, there are two sides with measurement which equals 16.
In the biggest, there are the same sides but with another measurement: 20.
Knowing that we know that the biggest triangle follows the same structure as the smallest, but a teeny bit bigger, right?
So, as we can say that they follow the same proportionality, let's equal them:
[tex]\begin{gathered} \frac{16}{20}=\frac{24}{n} \\ \\ \text{multiplying accross, we will get:} \\ 16.n=24.20 \\ 16n=480 \\ n=\frac{480}{16} \\ n=30 \end{gathered}[/tex]
So, n = 30.
Another way:
we know that the same side before measured 16 and now measures 20, so we can write the proportion: 16/20.
If we simplify this fraction we will get 4/5, or in decimal, 0.8.
Now, we will divide the previous measure of the long side by this obtained proportion:
[tex]\frac{24}{0.8}=30[/tex]
