Respuesta :
Explanation:
We have to balance this equation:
___ H₂SO₄ + __ KOH ----> __ K₂SO₄ + __ H₂O
The first step is to determine the number of atoms of each element that we have on both sides of the equation.
___ H₂SO₄ + __ KOH ----> __ K₂SO₄ + __ H₂O
K: 1 K: 2
S: 1 S: 1
H: 3 H: 2
O: 5 O: 5
We have 1 atom of K on the left side of the equation and there are 2 atoms of K on the rigth side of the equation. To balance the number of K atoms we can change the coefficient for KOH and write a 2 there.
___ H₂SO₄ + 2 KOH ----> __ K₂SO₄ + __ H₂O
K: 2 K: 2
S: 1 S: 1
H: 4 H: 2
O: 6 O: 5
We balanced the K. The S atoms are already balanced. Let's focus on H. We have 4 atoms of H on the left and 2 atoms of H on the right side of the equation. We can change the coefficient for H₂O and write a 2 there to get 4 atoms of H on the right side.
___ H₂SO₄ + 2 KOH ----> __ K₂SO₄ + 2 H₂O
K: 2 K: 2
S: 1 S: 1
H: 4 H: 4
O: 6 O: 6
We balanced the H and we also changed the number of O atoms on the right side and also balanced them. The balanced equation is:
H₂SO₄ + 2 KOH ----> K₂SO₄ + 2 H₂O
Answer: H₂SO₄ + 2 KOH ----> K₂SO₄ + 2 H₂O
