Kinsley measured a city park
Scale of drawing : 13 milimeter and 5 meter
Actual width is 65 meter
Let the field in Milimeter is x
So,
[tex]\begin{gathered} 13\text{ milimeters and 5 meters=x milimeters and 65 meters} \\ \frac{13}{5}=\frac{x}{65} \\ \text{Apply cross multiplication} \\ x=\frac{13\times65}{5} \\ x=\frac{13\times13}{1} \\ x=169 \\ Park\text{in milimeters = 169} \\ So, \\ 13\text{ milimeters and 5 meters=169 milimeters and 65 meters} \end{gathered}[/tex]Answer: 13 milimeters and 5 meters = 169 milimeters and 65 meters
