Answer:
2842
Explanation:
The first multiple of 7 =7
The last multiple of 7 before 200 = 196
This problem forms an arithmetic sequence where:
• The first term, a= 7
,• The last term, l = 196
To determine the sum, we find first the number of multiples of 7 between 7 and 196.
[tex]\begin{gathered} \text{Number of multiples=}\frac{196}{7} \\ =28 \end{gathered}[/tex]For a sequence with first and last terms, its sum is:
[tex]\begin{gathered} S_n=\frac{n}{2}(a+l) \\ =\frac{28}{2}(7+196) \\ =14\times203 \\ =2842 \end{gathered}[/tex]The sum of all multiples of 7 between 1 to 200 is 2842.
•
