at the restauant we can choose 5 topping for a hamburger,
let us solve using combination,
[tex]^5C_0+^5C_1+^5C_2+^5C_3+^5C_4+^5C_5=[/tex]we know that,
[tex]^nC_0+^nC_1+^nC_2+\ldots+^nC_5=2^n[/tex]thus,
[tex]\begin{gathered} ^5C_0+^5C_1+^5C_2+^5C_3+^5C_4+^5C_5=2^5 \\ =32 \end{gathered}[/tex]hence, there are 32 ways to pick the toppings.