Given:
Sample size, n = 82
We have the repsonses on the table.
Suppose a student is randomly selected, let's determine the following probabilities.
Number that studied and pass = 22
Number of students that paased = 22 + 26 = 48
a) P(Did Study and Pass) =
[tex]P=\frac{\text{Number that studied and pass}}{\text{Total number of students}}=\frac{22}{82}=0.268[/tex]b) P(Did not Study and Fail):
Total number that failed = 10 + 24 = 34
Number that did not study and fail = 24
[tex]P=\frac{Number\text{ that did not study and fail}}{Total\text{ number of students}}=\frac{24}{82}=0.293[/tex]c) P(Pass or Did not Study):
[tex]P=\frac{26+22+24}{82}=\frac{72}{82}=0.878[/tex]d) P(Fail or did study):
[tex]P=\frac{10+24+22}{82}=0.683[/tex]e) P(Fail and Pass) = 0
This is zero since there is no inetrsection for students who fail and students who pass
ANSWER:
• P(Did Study and Pass) = 0.268
,• P(Did not Study and Fail) = 0.293
,• P(Pass or Did not Study) = 0.878
,• P(Fail or did Study) = 0.683
,• P(Fail and Pass) = 0
