An iron railroad railis 750 ft long when the temperature is 34°C. What is its length (in ft) when the temperature is -18°C? (Round your answer to at least 3 decimal placeFt

Respuesta :

Answer: Final length = 749.998 ft

Explanation:

We would assume that the coefficient of linear expansion of iron is 36 x 10^- 6/C

We would apply the formula for calculating linear thermal expansion which is expressed as

L1 = aL(θ2 - θ1)

where

L1 = change in length

L = original length

a = coefficient of linear expansion of iron

θ2 = final temperature

θ1 = initial temperature

From the information given,

L = 750

θ2 = - 18

θ1 = 34

a = 12 x 10^- 6/C

By substituting these values into the formula,

L1 = 36 x 10^- 6(- 18 - 34)

L1 = 36 x 10^- 6(- 52)

L1 = - 0.001872

Thus,

Final length - initial length = - 0.001872

Final length - 750 = - 0.001872

Final length = - 0.001872 + 750

Final length = 749.998 ft