Using the fact that:
[tex]W=P\Delta V[/tex]We could replace our values as follows:
[tex]\begin{gathered} W=17atm\cdot(71L-79L) \\ W=17atm\cdot(-8L) \\ W=-136J \end{gathered}[/tex]As you can see, the work done is negative since the gas is being compressed. Therefore,
The work done is -136J.
In kJ, the answer is -0.136kJ. Rounded to 2 significant digits, this is -0.14kJ