[tex](4,0)[/tex]
1) In this problem, let's solve this given system of equations by the method of Elimination.
We can start by adding both equations simultaneously:
[tex]\begin{gathered} 2x+3y=8 \\ 3x-3y=12 \\ --------- \\ 5x=20 \\ \\ \frac{5x}{5}=\frac{20}{5} \\ \\ x=4 \end{gathered}[/tex]
Now, that we know the quantity of x, let's plug it into any of those equations. Most of the time, we opt to plug it into the simpler equation.
[tex]\begin{gathered} 2x+3y=8 \\ 2(4)+3y=8 \\ 8+3y=8 \\ -8+8+3y=8-8 \\ 3y=0 \\ \frac{3y}{3}=\frac{0}{3} \\ \\ y=0 \end{gathered}[/tex]
2) Thus, the answer is (4,0)
