Given:
an equation is given as m² -5m - 14 = 0
Find:
we have to solve the given quadratic equation.
Explanation:
Compare the given equation with am² + bm + c = 0, we get
a = 1, b = -5, c = -14
we will solve the given equation as following
[tex]\begin{gathered} ()=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(1)(-14)}}{2(1)} \\ ()=\frac{5\pm\sqrt{25+56}}{2}=\frac{5\pm\sqrt{81}}{2} \\ ()=\frac{5\pm9}{2} \\ ()=\frac{5+9}{2},\frac{5-9}{2} \\ ()=\frac{14}{2},-\frac{4}{2} \\ ()=7,-2 \end{gathered}[/tex]Therefore, the solution of given equation is m = 7, -2
