Respuesta :

Given the system of equations:

3x + 3y = 18

2x + y = 4

Let's solve the system of equations using the elimination method.

Multiply one equation by a number which makes one variable of each equation opposite.

Multiply equation 2 by -3:

3x + 3y = 18

-3(2x + y) = -3(4)

3x + 3y = 18

-6x - 3y = -12

Add both equations:

3x + 3y = 18

+ -6x - 3y = -12

_________________

-3x = 6

Divide both sides by -3:

[tex]\begin{gathered} \frac{-3x}{-3}=\frac{6}{-3} \\ \\ x=-2 \end{gathered}[/tex]

Substitute -2 for x in either of the equations.

Take the second equation:

2x + y = 4

2(-2) + y = 4

-4 + y = 4

Add 4 to both sides:

-4 + 4 + y = 4 + 4

y = 8

Therefore, we have the solutions:

x = -2, y = 8

In point form, we have the solution:

(x, y) ==> (-2, 8)

ANSWER:

(-2, 8)