ANSWER:
0.004259 N
STEP-BY-STEP EXPLANATION:
Given:
qA = +13.13 nC
qB = -26.7 nC
d = y - x = 2.72 - 0 = 2.72 cm = 0.0272 m
We use Coulomb's law to calculate the force:
[tex]F=k\cdot\frac{q_A\cdot q_B}{d^2}[/tex]We substitute each value and calculate the force:
[tex]\begin{gathered} F=9\times10^9\cdot\frac{(13.13\times10^{-9})(26.7\times10^{-9})}{(0.0272)^2} \\ \\ F=0.004259\text{ N} \end{gathered}[/tex]The magnitude of the electric force on object A is 0.004259 N
