SOLUTION:
Step 1:
[tex]\frac{1}{8}\text{ -}\frac{1}{4}(3-\frac{1}{2})\text{ + }\frac{2}{3}[/tex]Step 2:
[tex]\frac{1}{8}\text{ - }\frac{1}{4}(2\frac{1}{2})\text{ + }\frac{2}{3}[/tex]Step 3:
[tex]\begin{gathered} \frac{1}{8}\text{ - }\frac{1}{4}(\frac{5}{2})\text{ +}\frac{2}{3} \\ \frac{1}{8}\text{ - }\frac{5}{8}\text{ + }\frac{2}{3} \\ \\ \frac{3\text{ - 15 + 16}}{24} \\ \\ \frac{4}{24}\text{ or }\frac{1}{6} \\ \end{gathered}[/tex]