From the question;
we are to determine if the point (-2, 11) is on the circle with radius 5 and center (2, 13)
The equation of a circle with a radius r and center (a, b) is given as
[tex](x-a)^2+(y-b)^2=r^2[/tex]
Hence, the equation of the circle with radius 5 and center (2, 13)
[tex]\begin{gathered} (x-2)^2+(y-13)^2=5^2 \\ (x-2)^2+(y-13)^2\text{ = 25} \end{gathered}[/tex]
Considering the point (-2, 11), we need to substitute the values for x and y
therefore, x = -2, y = 11
[tex]\begin{gathered} (-2-2)^2+(11-13)^2\text{ }\ne\text{ 25} \\ (-4)^2+(-2)^2\text{ }\ne\text{ 25} \\ 16\text{ + 4 }\ne\text{ 25} \\ 20\text{ }\ne\text{ 25} \end{gathered}[/tex]
Since LHS is not equal to RHS then the point (-2, 11) is not on the circle.
