From the given image, the Area of the floor can be calculated by removing/subtracting the area of the two triangles from the area of the rectangle.
Area of a rectangle is;
[tex]\begin{gathered} A_r=lb \\ A_r=36.72 \end{gathered}[/tex]Area of the two triangles;
[tex]\begin{gathered} A_t=\frac{1}{2}bh+\frac{1}{2}bh=\frac{1}{2}(18.18)+\frac{1}{2}(18.18) \\ A_t=18.18 \end{gathered}[/tex]The Area of the floor is;
[tex]\begin{gathered} A=A_r-A_t \\ A=36.72-18.18 \\ A=2592-324 \\ A=2268ft^2 \end{gathered}[/tex]