We have this equation
[tex]y-3x=4[/tex]The following is the slope intercept form
[tex]y=mx+b[/tex]add 3x on both sides of the equation
[tex]y-3x+3x=4+3x[/tex]simplify
[tex]y=4+3x[/tex]rearrange
[tex]y=3x+4[/tex]So, the above is the equation in slope-intercept form
Now, let's graph the equation
since this is a linear equation, we need to find 2 points and plot them in the chart
let's find point 1. Let's say x = 0 and replace: y = 3x+4 = 3*0 + 4 = 0 + 4 = 4
so, when x=0, then y = 4 , so our 1st point is (0,4)
now, let's suppose, y=0 , in that case, y = 3x + 4 = 0 , then 3x = -4 , so the value of x is -4/3 = -1.3333
in that case, our seconds point is (-4/3 , 0)
just to make sure, we can also plot a 3rd point, let's say we make x = 2, then y = 3*2 + 4 = 6 + 4 = 10
so, our 3rd point is (2, 10)
using the points above, we can plot something like this...
