From the information provided, observe that the three terms are connected by a common ratio.
The first term is multiplied by a value denoted as letter r (common ratio) to derive the second term. The second term is also multiplied by r to derive the third term, and so on.
Therefore;
[tex]\begin{gathered} 5\times r=4 \\ r=\frac{4}{5} \\ 4\times r=\frac{16}{5} \\ r=\frac{16}{5}\text{ / }\frac{4}{1} \\ r=\frac{16}{5}\times\frac{1}{4} \\ r=\frac{4}{5} \end{gathered}[/tex]From the above calculation, the common ratio is 4/5. Therefore, the 10th term in the sequence shall be;
[tex]\begin{gathered} T_n=a\times r^{n-1} \\ \text{Where;} \\ a=5,r=\frac{4}{5},n=\text{nth term} \\ T_{10}=5\times(\frac{4}{5})^{10-1} \\ T_{10}=5\times(\frac{4}{5})^9 \\ T_{10}=5\times\frac{262144}{1953125} \\ T_{10}=\frac{262144}{390625} \end{gathered}[/tex]The 10th term is as shown above. To round this figure to the nearest thousandth, we need to convert this fraction into a decimal.
Hence we would have;
[tex]\begin{gathered} T_{10}=\frac{262144}{390625} \\ T_{10}=0.67108864 \\ T_{10}\approx0.671\text{ (to the nearest thousandth)} \end{gathered}[/tex]