If it takes 299 calories to melt a mass of ice into water at a temperature of zero degrees Celsius then what was the mass of the ice in grams? A)0.0471 B)3.75 C)161000

If it takes 299 calories to melt a mass of ice into water at a temperature of zero degrees Celsius then what was the mass of the ice in grams A00471 B375 C16100 class=

Respuesta :

Given:

The heat absorbed by ice to melt into water is Q = 299 calories.

To find the mass of the ice in grams.

Explanation:

When the ice starts melting into water, the temperature of the system does not change, all the heat provided to the system is used up to convert the ice to water. This is known as latent heat of fusion.

The latent heat of fusion for water is

[tex]L_f=79.8\text{ cal/g}[/tex]

The formula to calculate mass is

[tex]Q=mL_f[/tex]

Substituting the values, the mass will be

[tex]\begin{gathered} m=\frac{Q}{L_f} \\ =\frac{299}{79.8} \\ =3.75\text{ g} \end{gathered}[/tex]

Final Answer: The mass of ice is 3.75 g