The probability that the sample mean would be greater than 133.5 is 0.9926
Explanation:Given:
Mean = 137
Standard deviation = 8
Sample = 31
To find the probability that the sample mean would be greater than 133.5, we have:
[tex]\begin{gathered} z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}} \\ \\ =\frac{133.5-137}{\frac{8}{\sqrt{31}}}=-2.4359 \\ \\ P(X>133.5)=1-P(z<-2.4359) \\ =1-0.0074274 \\ \approx0.9926 \end{gathered}[/tex]