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A new cell tower is being constructed and needs a guy-wire connected 137 feet up the tower and it needs to make an angle of 56° with the ground. What length does the wire need to be?

Respuesta :

[tex]\begin{gathered} \sin (56)=\frac{137}{wire´s\text{ length}} \\ wire´s\text{ length=}\frac{137}{\sin(56)} \\ wire´s\text{ length=165.25fe}et \\ the\text{ wires length is 165.25 fe}et \end{gathered}[/tex]

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