therefore, the resistivity is 0.019210 miliOhms
ExplanationStep 1
The resistance of a cylindrical segment of a conductor is equal to the resistivity of the material times the length divided by the area
[tex]\begin{gathered} R=\rho\frac{L}{A} \\ where\text{ }\rho\text{ is the resistivity of the material} \\ L\text{ is the lenght} \\ A\text{ is the area} \end{gathered}[/tex]so
Step 1
a)let
[tex]\begin{gathered} \rho=1.7*10^{-8} \\ L=2.84 \\ diameter=\text{ 0.04 m} \\ Area\text{ = unknown} \end{gathered}[/tex]bI find the area
the area of a circle is given by:
[tex]area=\pi(\frac{diameter^2}{4})[/tex]so, replace
[tex]\begin{gathered} area=\pi(\frac{0.04m^2}{4}) \\ Area=0.0025132741\text{ m}^2 \end{gathered}[/tex]c) now, we can replace the values in the formula
[tex]\begin{gathered} R=\rho\frac{L}{A} \\ R=1.7*10^{-8}\frac{2.84\text{ m}}{0.0025132741\text{ m}^2} \\ R=1.9*10^{-5}\text{ ohm} \\ to\text{ convert into miliOhms , multiply by 1000} \\ R=R=\frac{1.9\text{ohm}}{10^{5}}*\frac{1000\text{ miliOhms}}{1\text{ Ohms}}=0.01921\text{ ohms} \end{gathered}[/tex]therefore, the resistivity is 0.019210 miliOhms
I hope this helps yo u
