It is given that two adults and three children pay $88.
Represent it as equation
2x+3y=88
Then three adults and four children pay $124.
It is written is equation form as follows.
3x+4y=124
Here x is adults' price and y is children's price.
Solve the system of equation as follows.
[tex]\begin{gathered} 3x+4y=124 \\ 2x+3y=88 \\ 6x+8y=248 \\ 6x+9y=264 \end{gathered}[/tex]Now subtract each of the last two equations to get -y=-16
Hence y = 16
Substitute in equation 1, we get
[tex]\begin{gathered} 2x+48=88 \\ 2x=40 \\ x=20 \end{gathered}[/tex]Therefore, adult price is $20 and children price is $16
