Given data:
The depth of water increases per hour is d= 13.5 in/hour.
The given time is t= 6 hours.
The amount of water added is,
[tex]\begin{gathered} W=d\times t \\ =(13.5)(6)\text{ }in \\ =81\text{ in} \\ =81\text{ in(}\frac{1\text{ ft}}{12\text{ in}}) \\ =6.75\text{ ft} \end{gathered}[/tex]Thus, 6.75 feet of water added in 6 hours.
