Given:
Charge of an electron = -1.6 x 10⁻¹⁹ C
Let's show that there are about 3 x 10¹⁸ electrons in 5 x 10⁸ nC of charge.
Using the given charge of an electron, to find the number of electrons in 5 x 10⁸ nC of charge, we have:
[tex]\frac{5*10^8*10^{-9}}{1.6*10^{-19}}=3*10^{18}[/tex]
Now, let's prove this equation is true.
Simplify the left side:
[tex]\begin{gathered} \frac{5*10^8*10^{-9}}{1.6*10^{-19}} \\ \\ =\frac{5*10^{-1}}{1.6*10^{-19}} \\ \\ =3.125*10^{-18}\text{ electrons} \end{gathered}[/tex]
We can see the number of electrons calculated is equivalent to the number of electrons given.
Therefore, we have shown that there are about 3 x 10¹⁸ electrons in 5 x 10⁸ nC of charge.
ANSWER:
Number of electrons = 3.125 x 10¹⁸ electrons
