Vertex of a parabola
The point where the parabola intersects its axis of symmetry is called the "vertex" and is the point where the parabola is most sharply curved.
The given function is,
[tex]f(x)=2x^2+14x+11[/tex]
We will apply graphical method to obtain the solution to the vertex of the parabola
From the graph above, the vertex of the parabola is (- 3.5, - 13.5) which can also be represented into fraction as
[tex](-\frac{7}{2},-\frac{27}{2})[/tex]
And finally, the parabola opens upward.
Hence, the correct option is Option 2.
