Given the information on the problem, we have the following parallelogram:
since the perimeter is 34, we can write the following equation:
[tex]2(3x-6)+2(2x-7)=34[/tex]solving for x, we get:
[tex]\begin{gathered} 2(3x-6)+2(2x-7)=34 \\ \Rightarrow6x-12+4x-14=34 \\ \Rightarrow10x-26=34 \\ \Rightarrow10x=34+26=60 \\ \Rightarrow x=\frac{60}{10}=6 \\ x=6 \end{gathered}[/tex]now that we have that x = 6, we can find the measure of the sides:
[tex]\begin{gathered} x=6 \\ 3(6)-6=18-6=12 \\ 2(6)-7=12-7=5 \end{gathered}[/tex]therefore, x = 6 and the shorter side measures 5 units
