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SOLUTION

From the graph

The slope of line A is

[tex]m=\frac{60-20}{2-0}=20[/tex]

The slope of line B is

[tex]n=\frac{80-60}{6-2}=5[/tex]

The slope of line C is

[tex]p=\frac{110-80}{9-6}=10[/tex]

The least segment is the segment with the least slope.

The required arrangement is

[tex]B,C,A[/tex]

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