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We know that 50.5 grams of sucrose is equal to 0.148 moles of sucrose, we need to use this information to find the molarity (the unit of measuring concentration). We can calculate the molarity (M) or concentration of a solution in moles / L if we know the volume of the solution in liters (L).Let’s say you mixed your 0.148 moles of sucrose into 0.0012 L of solution.What is the molarity of this solution?

Respuesta :

Answer:

123.33mol/L

Explanations:

The formula for calculating the molarity of a solution is expressed as:

[tex]\begin{gathered} \text{Molarity}=\frac{moles\text{ of solute}}{litres\text{ of solution}} \\ \end{gathered}[/tex]

Given the following parameters

• Moles, of sucrose (solute) = 0.148 moles

• Litres ,of solution = 0.0012L

Substitute the given parameters into the formula;

[tex]\begin{gathered} \text{Molarity}=\frac{0.148\text{moles}}{0.0012L} \\ \text{Molarity}=123.33\text{mol/L} \end{gathered}[/tex]

Therefore the molarity of this solution is 123.33mol/L.

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