Respuesta :
Answer:
1200 N
Explanation:
First, we need to calculate how much time the force was applied. If the stone traveled at 20.0m/s and made a 0.20 cm deep dent, the time is equal to
[tex]\text{ Avg }speed=\frac{distance}{time}\Rightarrow time=\frac{distace}{Avg\text{ }speed}[/tex]Where the distance is 0.20 cm = 0.0020 m and the average speed can be calculated as:
[tex]\text{ avg speed = }\frac{v_i+v_f}{2}=\frac{20\text{ m/s + 0 m/s}}{2}=10\text{ m/s}[/tex]Therefore, the time is equal to
[tex]time=\frac{0.0020\text{ m}}{10\text{ m/s}}=0.0002\text{ s}[/tex]Then, the force can be calculated using the following equation for impulse
[tex]\begin{gathered} Ft=mv \\ F=\frac{mv}{t} \end{gathered}[/tex]Where m is the mass, v is the speed and t is the time, so replacing m = 0.012 kg, v = 20 m/s and t = 0.0001 s, we get
[tex]F=\frac{0.012\text{ kg \lparen20 m/s\rparen}}{0.0002\text{ s}}=1200N[/tex]So, the average force was 1200 N
