Given:
object size: 1 cm
object distance (do): 10 cm
mirror focal length (f): 15 cm
Required:
Image distance (di),
magnification
image characteristics.
Equations needed:
[tex]\begin{gathered} \frac{1}{d_i}+\frac{1}{d_o}=\frac{1}{f} \\ \text{magnification}=-\frac{d_i}{d_o} \end{gathered}[/tex]Solution:
[tex]\begin{gathered} \frac{1}{d_i}+\frac{1}{10}=\frac{1}{15} \\ \frac{1}{d_i}=\frac{1}{15}-\frac{1}{10} \\ \frac{1}{d_i}=\frac{2}{30}-\frac{3}{30} \\ \frac{1}{d_i}=\frac{-1}{30}_{} \\ d_i=-30\text{ cm} \\ \\ \text{magnification}=-\frac{-30}{10}=3 \end{gathered}[/tex]Location: 30 cm "inside" the mirror (di = -30)
Orientation: Upright (magnification > 0)
Size: 3 cm (object size multiplied by magnification)
Type: virtual image (di < 0)
