The given equation is:
[tex]2x\text{ - 10 }\leq\text{ 6}[/tex]To simply this, just keep the x term on the left side and others at the right side. Therefore,
[tex]2x\text{ }\leq\text{ 6 + 10}[/tex][tex]2x\text{ }\leq\text{ 16}[/tex][tex]x\text{ }\leq\text{ }\frac{16}{2}[/tex]or
[tex]x\text{ }\leq\text{ 8}[/tex]Hence, the solution is x =< 8.