[tex]\begin{gathered} a)\frac{13}{50} \\ b)33.28fl.oz \end{gathered}[/tex]
1) We can write the following ratio for this, considering the ratios and the quantities:
a)
[tex]\begin{gathered} \frac{50}{1}=\frac{13}{x} \\ 50x=13 \\ x=\frac{13}{50}\text{ (or 0.26g)} \end{gathered}[/tex]
Notice that on the left side, the ratio gas/oil, and on the right side is the quantity of gas and the unknown quantity of oil.
So, so far we have 13/50 gallons of oil that must be mixed with gasoline.
b) For now, we need to convert that from gallons to fluid ounces so we can write out the following product:
[tex]\begin{gathered} x=\frac{13}{50}\times128 \\ x=33.28fl\text{ oz} \end{gathered}[/tex]
So 13/50 or 0.26 gallons of oil. b) 33.28 fl oz.
