m= 2.4 kg
Amplitude = maximum displacement = 3 cm
period = time to complet 1 cycle = T = 0.8 s
frequency = 1/T = 1 /0.8 = 1.25 hz
angular frequency = ω= 2 pi f = 2 pi x 1.25 = 7.85 rad/s
Constant of the spring:k
ω = √k/m
k = ω^2 m = (7.85)^2 * 2.4 = 147.894 N/m
Answers:
A) Period = 0.8 s
B) Frequency = 1.25 hz
C) Angular Frequency= 7.85 rad/s
D) Amplitude =3cm
E) Spring Constant = 147.894 N/m