Reaction 1
Solid sulfur can be represented by S(s) and solid iron is represented by Fe(s). Note the little s stands for solid.
Iron(III) sulfide will have the following formula:
[tex]Fe^{3+}+S^{2-}\rightarrow Fe_2S_3[/tex]Reaction 2
Hyrogen gas can be represented by H2(g) and Iron (III) Oxide will have the following formula:
[tex]Fe^{3+}+O^{2-}\rightarrow Fe_2O_3[/tex]The products are H2O(l) and Fe(s). Therefore:
[tex]H_{2(g)}+Fe_2O_{3(g)}\rightarrow H_2O_{(l)}+Fe_{(s)}[/tex]Reaction 3
Magnesium metal can be representd as Mg(s) and hydrochloric acid is HCl. Magnesium chloride will have the following formula:
[tex]Mg^{2+}+Cl^-\rightarrow MgCl_2[/tex]Therefore, the equation can be writen as:
[tex]Mg_{(s)}+HCl_{(aq)}\rightarrow MgCl_{2(aq)}+H_{2(g)}[/tex]Reaction 4
Magnesium sulfide has the following formula:
[tex]Mg^{2+}+S^{2-}\rightarrow MgS[/tex]The reaction can be writen thus as:
[tex]MgS_{(s)}+HCl_{(aq)}\rightarrow H_2S_{(g)}+MgCl_{2(aq)}[/tex]Reaction 5
Oxygen gas can be represented as O2(g) and solid copper as Cu(s). Copper (II) oxide has the following formula:
[tex]Cu^{2+}+O^{2-}\rightarrow CuO[/tex]The reaction can be writen thus as:
[tex]O_{2(g)}+Cu_{(s)}\rightarrow CuO_{(s)}[/tex]
