Solve each inequality [tex] - 3e - 10 \leqslant - 14[/tex][tex] \frac{c}{2} + 8 \ \textgreater \ 11[/tex][tex]15 \leqslant 3 - 4s[/tex][tex] \frac{3}{4}j + 1 \ \textgreater \ 4[/tex]

Respuesta :

1.

[tex]\begin{gathered} -3e-10\le-14 \\ -3e\le-14+10 \\ -e\le\frac{-4}{3} \end{gathered}[/tex]

is you remove a negative sign you have to rotate the symbol of < or >

[tex]e\ge\frac{4}{3}[/tex]

2.

[tex]\begin{gathered} \frac{c}{2}+8>11 \\ \frac{c}{2}>11-8 \\ c>\frac{3}{2} \end{gathered}[/tex]

3.

[tex]\begin{gathered} 15\le3-4s \\ 15-3\le-4s \\ 12\le-4s \\ \frac{12}{4}\le-s \\ 3\ge s \\ s\le3 \end{gathered}[/tex]

4.

[tex]\begin{gathered} \frac{3}{4}j+1>4 \\ \frac{3}{4}j>4-1 \\ \frac{1}{4}j>\frac{3}{3} \\ j>4\times1 \\ j>4 \end{gathered}[/tex]