a ladder is leaning against a wall. the ladder touches the wall 15 feet above the ground. how far is the bottom of the ladder from the wall if the length of the ladder is one foot more than twice its distance from the wall

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01-12-2022
Mathematics

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a ladder is leaning against a wall. the ladder touches the wall 15 feet above the ground. how far is the bottom of the ladder from the wall if the length of the ladder is one foot more than twice its distance from the wall

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QWTiffany QWTiffany · Answer 1 · 2022-12-05T15:52:07+01:00

The bottom of the ladder is at 8 feet from the wall.

The position of the ladder will form a right angled triangle with the wall. The perpendicular is 15 feet. Let the distance between ladder and wall be x. Thus, the length of the ladder will be 2x + 1. Forming a equation according to Pythagoras theorem.

(2x + 1)² = x² + 15²

Expanding the equation

4x² + 1 + 4x = x² + 225

Rewriting the equation

4x² - x² + 4x = 225 - 1

Performing subtraction

3x² + 4x = 224

3x² + 4x - 224 = 0

Factorizing the quadratic equation, we get -

x = -9.3 and 8

The distance can not be negative. Hence, the value of x is 8.

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