The value of the probability p(x > 105.0) for the given normal random variable is found as 0.6915.
For the stated question -
The formula for the z score -
z = (x - μ)/σ
In which,
μ = 140 and σ = 20
Put the values-
z = (150 - 140)/20
z = 0.5
p(x > 105.0) = p(z > 0.5)
p(x > 105.0) = 0.6915
Thus, the value of the probability p(x > 105.0) for the given normal random variable is found as 0.6915.
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The complete question is-
suppose x is a normal random variable with μ = 140 and σ = 20 and find p(x > 105.0).