A belt connects two pulleys. Larger pulley has a radius of 60cm and the smaller pulley has a radius of 20cm. The smaller pulley runs at 48 revolutions per min
a) how many revolutions per minute does the larger pulley run at? [hint: find the circumference of each pulley]
(i got 16 rev per min i don't know if that's correct)
b) find angular speed of the smaller pulley in radians per min
c) find the angular speed of the larger pulley in radians per min
d) find the speed of the smaller pulley in cm per min

A pseudovector used in physics to express how quickly an object's angular position or orientation changes over time is called an angular velocity, rotational velocity, or angular frequency vector.

For the smaller pulley, it does 48 rpm (revolutions per minute) each revolution is 360 degrees. This indicates that the pulley completes one revolution every second .

radians / π = degrees / 180

radians = πx 360 / 180 = 2 π radians per second

The distance covered by both pulleys is equivalent for the larger pulley.

then d1 = d2

every second, small pulley covers a distance of 40π (small pulley circumference) = d1

d2 = 40π = 120π (large pulley circumference) x factor (f)

f = 1/3

a) the revolutions per min by larger pulley=16 rpm

b) the speed of smaller pulley = 3*2π=6π=6rad/sec=360rad/min

c) then speed of the large pulley = 1/3 * 2π = 2/3 π = 0.66 rad/sec=39.6rad/min

d)the speed of smaller pulley=7200 cm/min

Therefore the solution to this question of 2 pulleys is )16 rpm

b)360 rad/min c)39.6 rad/min d) 7200cm/min

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