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You had a job offer from two companies, company a and company b. company a, with 28,000 employees, offers a starting salary of $45,000 and a raise of $1,000 every year. company b, with 10,500 employees, offers a starting salary of $40,000 and a raise of 3% every year.
a. After how many years would Janine's salary be the same with both companies?
b. What would that salary be?

Respuesta :

  • After 25 years Janine's salary would be the same with both companies.
  • That salary would be $70,000.

The equation in mathematics is used to help you solve the problem. With equations, you can solve problems easily. Equation, in mathematics, is the form of the values that you want to find.

Assume the number of years be y

Then, the equation will be:

Company A = $45,000 + ($1,000 × y)

Company A = $45,000 + $1,000y

Company B = $40,000 + ($1,200 × y)

Company B = $40,000 + $1,200y

Collect them to become one equation:

$45,000 + $1,000y = $40,000 + $1,200y

Collect like terms

$45,000 -  $40,000 = $1,200y- $1,000y

5000y = 200

y = 5000/200

y = 25.

The number of years will be 25 years

b. The salary will be:

= $45,000 + $1,000y

= $45,000 + $1,000 (25)

= $45,000 + $25,000y

= $70,000

The salary is $70,000

Learn more about equation here, https://brainly.com/question/971537

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