The angle of CAE is 22
A line known as a perpendicular bisector cuts a specified line segment precisely in half, creating a 90° angle at the junction. The intersection of a line segment's midpoint with a perpendicular bisector. It can be built with a compass and a ruler. On both sides of the line segment being divided, it forms a 90° angle.
Perpendicular bisector of ABC's side AB crosses BC at point E and side AB at point D. Additionally, m CAB = 82 and m C = 68.
Adopt A E.
In ABC, the triangle's angle sum property is A+B+C=180°.
82°+∠B+68°=180°
∠B= 180°-150°
∠B=30°
AD=B DDE is a perpendicular bisector in A DE and B DE.
If ADE=BDE=90°
DE is common.
Δ A DE ≅ Δ E DB→→[S AS]
∠DEB=∠D A E→→[CPCT]----(1)
In Δ DBE
∠EDB + ∠DBE+∠BED=180°→→Angle sum property of Triangle.
90° +30°+∠BED=180°
∠BED=180°-120°
∠BED=60°
So, ∠BAE=∠BED=60°------[using (1)]
∠CAE=∠CAB - ∠BAE
= 82°-60°
= 22°
Therefore the angle CAE is 22
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