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Area=1/2.b.c.sinA


Area=1/2.14.12.sin78


Area=84.0,97


Area=82,1

Hence, the area of the triangle will be - 82.32 square units.

We have a triangle with ∠A =78 degrees, b = 14, c = 12.

We have to find the area of this triangle.

What is the formula to calculate the area of triangle with ∠A = [tex]\alpha ^{o}[/tex] , b = x , c = y ?

The formula to calculate the area of this triangle is -

Area = [tex]\frac{1}{2}\times b\times c\times sin\alpha[/tex]

According to the question -

b = 14 units

c = 12 units

∠A =78 degrees

Therefore, using the formula discussed above, we get -

Area = [tex]\frac{1}{2}[/tex] x 14 x 12 x sin (78) = 7 x 12 x 0.98 = 82.32 square units.

Hence, the area of the triangle will be - 82.32 square units.

To solve more questions on area of triangle, visit the link below -

https://brainly.com/question/15442893

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