Answer:
3.71 m/s^2
Explanation:
The acceleration of gravity on the surface of a planet can be found by using the following formula:
[tex]g=\frac{GM}{r^2}[/tex]
where
[tex]G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}[/tex] is the gravitational constant
[tex]M=6.39\cdot 10^{23} kg[/tex] is the mass of the planet (in this case, Mars)
[tex]r=3.39\cdot 10^6 m[/tex] is the radius of the planet (in this case, Mars)
Substituting the numbers into the formula, we find
[tex]g=\frac{(6.67\cdot 10^{-11})(6.39\cdot 10^{23} kg)}{(3.39\cdot 10^6 m)^2}=3.71 m/s^2[/tex]
