Respuesta :
Standard form is ax^2 + bx + c = 0
(2x + 1)(x - 2) = 0
Distribute to get into standard form
2x^2 - 4x + x - 2 = 0
2x^2 - 3x - 2 = 0
a = 2, b= -3, c = -2
A is your answer
(2x + 1)(x - 2) = 0
Distribute to get into standard form
2x^2 - 4x + x - 2 = 0
2x^2 - 3x - 2 = 0
a = 2, b= -3, c = -2
A is your answer
Answer:
Option A - a=2 , b=-3 , c=-2
Step-by-step explanation:
Given : Equation [tex](2x+1)(x-2)=0[/tex]
To find : Give the values of a, b, and c from the standard form of the equation?
Solution :
The standard form of the equation is form by multiplying the factors.
Solving by multiplication,
[tex](2x+1)(x-2)=0[/tex]
[tex]2x^2-4x+x-2=0[/tex]
[tex]2x^2-3x-2=0[/tex]
Comparing with general quadratic equitation,[tex]ax^2+bx+c=0[/tex]
a=2 , b=-3 , c=-2
Therefore, Option A is correct.
The values in standard form of equation are a=2 , b=-3 , c=-2.