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Identify the center and radius of a circle with equation (x-5)^2+(x+3)^2=25

A-center at (5,-3) ;radius :25

B-center at (5,-3) ; radius : 5

C-center at (-5,3) : radius ; 25

D- center at (-5,3) radius : 5

Respuesta :

[tex]\bf (x-5)^2+(x+3)^2=25\implies (x-5)^2+[x-(-3)]^2=5^2\\\\ -----------------------------\\\\ \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center\ ({{ h}},{{ k}})\qquad radius={{ r}}[/tex]

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