Consider circle T with radius 24 in. and θ = 5pi/6 radians. What is the length of minor arc SV?

20π in.
28π in.
40π in.
63π in.

Respuesta :

By definition, the arc length is given by:

[tex] S = R * theta
[/tex]

Where,

R: radius of the circle

theta: central angle

Therefore, substituting values we have:

[tex] S = (24) * (\frac{5}{6}\pi)

S = 20\pi
[/tex]

Thus, the length of the minor arc SV is given by:

20π in

Answer:

the length of minor arc SV is:

20π in

option 1

The length of the arc is equal to 20π in

Data;

  • θ = 5π/6 radians
  • radius = 24in

Length of an Arc

To find the length of the arc, we can either convert the angle from radians to degree and solve.

[tex]1rad * 180/\pi = degree\\5\pi /6 * 180/\pi = ?\\5/6 * 180 = 150^0[/tex]

The length of an arc is given as

[tex]L_a_r_c= \frac{\theta}{360}*2\pi r\\ L_a_r_c = \frac{150}{360} *2\pi *24\\ L_a_r_c = 20\pi[/tex]

From the calculation above, the length of the arc is equal to 20π.

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