Respuesta :
1) Write the balanced equation
2 H2O ----> 2 H2 + O2
2) State the molar ratios:
2 mol H2O : 2 mol H2 : 1 mol O2.
3) Write the proportion with the theoretical ratios and the actual data:
[2 mol H2 / 1 mol O2 ] = x mol H2 / 6.28 mol O2]
You can realize that this tells that the number of moles of H2 produced is the double of the number of moles of O2 produced.
4) Solve for x
x = 6.28 mol O2 * 2 mol H2 / 1 mol O2 = 12.56 mol O2.
Answer: option C. 12.6 mol
2 H2O ----> 2 H2 + O2
2) State the molar ratios:
2 mol H2O : 2 mol H2 : 1 mol O2.
3) Write the proportion with the theoretical ratios and the actual data:
[2 mol H2 / 1 mol O2 ] = x mol H2 / 6.28 mol O2]
You can realize that this tells that the number of moles of H2 produced is the double of the number of moles of O2 produced.
4) Solve for x
x = 6.28 mol O2 * 2 mol H2 / 1 mol O2 = 12.56 mol O2.
Answer: option C. 12.6 mol
12.6 mol moles of hydrogen are produced when 6.28 mol of oxygen forms.
The correct option is C.
What are moles?
The mole is the amount of substance in a system that includes the same number of elementary units as there are atoms in 0.012 kilograms of carbon 12; it is represented by the sign "mol."
Given,
The balanced equation
[tex]\bold{ 2H_2O = 2H_2 + O_2}[/tex]
The molar ratio is
[tex]\bold{2\; mol\; H_2O : 2\; mol\; H_2 : 1\; mol\; O_2.}[/tex]
The proportion with the theoretical ratio
[tex]\bold{ \dfrac{2 mol H_2}{1 mol O_2}= \dfrac{x mol H_2}{ 6.28 mol \;O_2} }[/tex]
[tex]\bold{x = 6.28\; mol O_2 \times \dfrac{2\; mol H_2}{1 mol O_2 } = 12.56\; mol\; O_2.}[/tex]
Thus, the moles of hydrogen produced is (C). 12.6 mol.
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