contestada

Consider this equilibrium: COCl2(g) CO(g) + Cl2(g) Keq = 8.1 x 10-4. What is true for this system? [COCl2] < [CO][Cl2] [COCl2] = [CO][Cl2] [COCl2] > [CO][Cl2]

Respuesta :

I'm pretty sure the answer here is C.
Dejanras

Answer is: [COCl₂] > [CO][Cl₂].

Chemical reaction: COCl₂(g) ⇄ CO(g) + Cl₂(g); Keq = 8.1 x 10⁻⁴.

Keq = [CO] · [Cl₂] / [COCl₂]; equilibrrium constant of chemical reaction.

[CO] · [Cl₂] / [COCl₂] = 0.00081.

Equilibrium product concentration is much more less than equilibrium concentration of reactant.