Respuesta :
Capacitance is charge/volts ratio. So C=(1.0e-10C)/100V = 1e-12F. Or 1pF where pF is picoFarad
Answer : The charge stored in the system is [tex]1\times 10^{-12}\ C[/tex]
Explanation :
It is given that,
Stored charge, [tex]Q=1\times 10^{-10}\ C[/tex]
Voltage, [tex]V=100\ V[/tex]
We know that the capacitance of a system is given by :
[tex]C=\dfrac{Q}{V}[/tex]
[tex]C=\dfrac{1\times 10^{-10}\ C}{100\ V}[/tex]
[tex]C=1\times 10^{-12}\ C[/tex]
So, the correct option is (C).
Hence, it is the required solution.