Answer:
Float more above the water level
Explanation:
As we know that during flotation of the force balance equation is given as
[tex]F_g = F_b[/tex]
weight of the cork is balanced by the buoyancy force due to liquid
so here we can say
[tex]mg = \rho V g[/tex]
V = volume of submerged part of the cork
now we have
[tex]V = \frac{m}{\rho}[/tex]
now as we add more salt in the water then the density of water will increase due to which the submerged part of the volume will decrease as we know that it is inversely depends on density of the water
so here submerged volume will decrease so cork will float more part above the liquid level
