What is the value of x?

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x=

A right triangle. The legs are labeled x and twelve, and the hypotenuse is labeled thirteen.

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Pythagoras says that x²+12²=13², so x=√(169-144)=√25=5

ABC is a right-angled triangle, the value of x is 8.

What is the Pythagoras theorem?

The Pythagoras theorem is defined as;

[tex]\rm Hypotenuse ^2=Perpendicular^2+Base^2\\\\[/tex]

From the given figure, it is given that ABC is a right-angled triangle that is right-angled at B and AC=10, AB=x, and BC=6.

Now, since, ABC is a right-angled triangle, therefore we can apply the Pythagoras theorem to this triangle, therefore we have;

[tex]\rm Hypotenuse ^2=Perpendicular^2+Base^2\\\\ AC^2=AB^2+BC^2\\\\10^2=x^2+6^2\\\\100=x^2+36\\\\x^2=100-36\\\\x^2=64\\\\x^2=8^2\\\\x=8[/tex]

Hence, the value of x is 8.

Learn more about Pythagoras' theorem here;

https://brainly.com/question/3466922

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